Solve for y
y=-\left(2x+1\right)^{2}+7
Solve for x (complex solution)
x=\frac{-\sqrt{7-y}-1}{2}
x=\frac{\sqrt{7-y}-1}{2}
Solve for x
x=\frac{-\sqrt{7-y}-1}{2}
x=\frac{\sqrt{7-y}-1}{2}\text{, }y\leq 7
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y=-\left(4x^{2}+4x+1\right)+7
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+1\right)^{2}.
y=-4x^{2}-4x-1+7
To find the opposite of 4x^{2}+4x+1, find the opposite of each term.
y=-4x^{2}-4x+6
Add -1 and 7 to get 6.
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