Solve for y
y=-\frac{\left(x-4\right)^{3}}{8}
Solve for x
x=-2\sqrt[3]{y}+4
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y=-\left(\frac{1}{8}x^{3}-\frac{3}{2}x^{2}+6x-8\right)
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(\frac{1}{2}x-2\right)^{3}.
y=-\frac{1}{8}x^{3}+\frac{3}{2}x^{2}-6x+8
To find the opposite of \frac{1}{8}x^{3}-\frac{3}{2}x^{2}+6x-8, find the opposite of each term.
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