Solve for x
x=\frac{3-3y}{8}
Solve for y
y=-\frac{8x}{3}+1
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-\frac{8}{3}x+1=y
Swap sides so that all variable terms are on the left hand side.
-\frac{8}{3}x=y-1
Subtract 1 from both sides.
\frac{-\frac{8}{3}x}{-\frac{8}{3}}=\frac{y-1}{-\frac{8}{3}}
Divide both sides of the equation by -\frac{8}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y-1}{-\frac{8}{3}}
Dividing by -\frac{8}{3} undoes the multiplication by -\frac{8}{3}.
x=\frac{3-3y}{8}
Divide y-1 by -\frac{8}{3} by multiplying y-1 by the reciprocal of -\frac{8}{3}.
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