Solve y=-3/x+1-2

$$y = - \frac { 3 } { x + 1 } - 2$$

Solve for x

$$x=-\frac{y+5}{y+2}$$

$$y\neq -2$$

Steps for Solving Linear Equation

Variable x cannot be equal to -1 since division by zero is not defined. Multiply both sides of the equation by x+1.

$$y\left(x+1\right)=-3+\left(x+1\right)\left(-2\right)$$

Use the distributive property to multiply y by x+1.

$$yx+y=-3+\left(x+1\right)\left(-2\right)$$

Use the distributive property to multiply x+1 by -2.

$$yx+y=-3-2x-2$$

Subtract 2 from -3 to get -5.

$$yx+y=-5-2x$$

Add 2x to both sides.

$$yx+y+2x=-5$$

Subtract y from both sides.

$$yx+2x=-5-y$$

Combine all terms containing x.

$$\left(y+2\right)x=-5-y$$

The equation is in standard form.

$$\left(y+2\right)x=-y-5$$

Divide both sides by y+2.

$$\frac{\left(y+2\right)x}{y+2}=\frac{-y-5}{y+2}$$

Dividing by y+2 undoes the multiplication by y+2.

$$x=\frac{-y-5}{y+2}$$

Divide -5-y by y+2.

$$x=-\frac{y+5}{y+2}$$

Variable x cannot be equal to -1.

$$x=-\frac{y+5}{y+2}\text{, }x\neq -1$$

Solve for y

$$y=-\frac{2x+5}{x+1}$$

$$x\neq -1$$