Solve y=-3/4x(-1)+3

$$y = - \frac { 3 } { 4 } x ( - 1 ) + 3$$

Solve for x

$$x=\frac{4\left(y-3\right)}{3}$$

Steps for Solving Linear Equation

Multiply -\frac{3}{4} and -1 to get \frac{3}{4}.

$$y=\frac{3}{4}x+3$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{4}x+3=y$$

Subtract 3 from both sides.

$$\frac{3}{4}x=y-3$$

Divide both sides of the equation by \frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{4}x}{\frac{3}{4}}=\frac{y-3}{\frac{3}{4}}$$

Dividing by \frac{3}{4} undoes the multiplication by \frac{3}{4}.

$$x=\frac{y-3}{\frac{3}{4}}$$

Divide y-3 by \frac{3}{4} by multiplying y-3 by the reciprocal of \frac{3}{4}.

$$x=\frac{4y}{3}-4$$

Solve for y

$$y=\frac{3\left(x+4\right)}{4}$$

Solution Steps

Multiply -\frac{3}{4} and -1 to get \frac{3}{4}.

$$y=\frac{3}{4}x+3$$