Solve y=-3/2x+1quadx+1

$$y = - \frac { 3 } { 2 } x + 1 \quad x + 1$$

Solve for x

$$x=2-2y$$

Steps for Solving Linear Equation

Combine -\frac{3}{2}x and 1x to get -\frac{1}{2}x.

$$y=-\frac{1}{2}x+1$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{1}{2}x+1=y$$

Subtract 1 from both sides.

$$-\frac{1}{2}x=y-1$$

Multiply both sides by -2.

$$\frac{-\frac{1}{2}x}{-\frac{1}{2}}=\frac{y-1}{-\frac{1}{2}}$$

Dividing by -\frac{1}{2} undoes the multiplication by -\frac{1}{2}.

$$x=\frac{y-1}{-\frac{1}{2}}$$

Divide y-1 by -\frac{1}{2} by multiplying y-1 by the reciprocal of -\frac{1}{2}.

$$x=2-2y$$

Solve for y

$$y=-\frac{x}{2}+1$$

Solution Steps

Combine -\frac{3}{2}x and 1x to get -\frac{1}{2}x.

$$y=-\frac{1}{2}x+1$$