Solve y=-2/3x+3

$$y = - \frac { 2 } { 3 } x + 3$$

Solve for x

$$x=\frac{9-3y}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{2}{3}x+3=y$$

Subtract 3 from both sides.

$$-\frac{2}{3}x=y-3$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y-3}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$x=\frac{y-3}{-\frac{2}{3}}$$

Divide y-3 by -\frac{2}{3} by multiplying y-3 by the reciprocal of -\frac{2}{3}.

$$x=\frac{9-3y}{2}$$

Solve for y

$$y=-\frac{2x}{3}+3$$