Solve y=-2/3+(7-1)(62/3)

$$y = - \frac { 2 } { 3 } + ( 7 - 1 ) ( 6 \frac { 2 } { 3 } )$$

Solve for y

$$y = \frac{118}{3} = 39\frac{1}{3} \approx 39.333333333$$

Steps for Solving Linear Equation

Subtract 1 from 7 to get 6.

$$y=-\frac{2}{3}+6\times \frac{6\times 3+2}{3}$$

Multiply 6 and 3 to get 18.

$$y=-\frac{2}{3}+6\times \frac{18+2}{3}$$

Add 18 and 2 to get 20.

$$y=-\frac{2}{3}+6\times \frac{20}{3}$$

Express 6\times \frac{20}{3} as a single fraction.

$$y=-\frac{2}{3}+\frac{6\times 20}{3}$$

Multiply 6 and 20 to get 120.

$$y=-\frac{2}{3}+\frac{120}{3}$$

Divide 120 by 3 to get 40.

$$y=-\frac{2}{3}+40$$

Convert 40 to fraction \frac{120}{3}.

$$y=-\frac{2}{3}+\frac{120}{3}$$

Since -\frac{2}{3} and \frac{120}{3} have the same denominator, add them by adding their numerators.

$$y=\frac{-2+120}{3}$$

Add -2 and 120 to get 118.

$$y=\frac{118}{3}$$

Assign y

$$y≔\frac{118}{3}$$