Solve for x
x=12-4y
Solve for y
y=-\frac{x}{4}+3
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-\frac{1}{4}x+3=y
Swap sides so that all variable terms are on the left hand side.
-\frac{1}{4}x=y-3
Subtract 3 from both sides.
\frac{-\frac{1}{4}x}{-\frac{1}{4}}=\frac{y-3}{-\frac{1}{4}}
Multiply both sides by -4.
x=\frac{y-3}{-\frac{1}{4}}
Dividing by -\frac{1}{4} undoes the multiplication by -\frac{1}{4}.
x=12-4y
Divide y-3 by -\frac{1}{4} by multiplying y-3 by the reciprocal of -\frac{1}{4}.
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