Solve for x
x=\frac{3\left(y-3\right)}{8}
Solve for y
y=\frac{8x}{3}+3
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y=-\frac{1}{3}x+3x+3
Divide 9 by 3 to get 3.
y=\frac{8}{3}x+3
Combine -\frac{1}{3}x and 3x to get \frac{8}{3}x.
\frac{8}{3}x+3=y
Swap sides so that all variable terms are on the left hand side.
\frac{8}{3}x=y-3
Subtract 3 from both sides.
\frac{\frac{8}{3}x}{\frac{8}{3}}=\frac{y-3}{\frac{8}{3}}
Divide both sides of the equation by \frac{8}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y-3}{\frac{8}{3}}
Dividing by \frac{8}{3} undoes the multiplication by \frac{8}{3}.
x=\frac{3y-9}{8}
Divide y-3 by \frac{8}{3} by multiplying y-3 by the reciprocal of \frac{8}{3}.
y=-\frac{1}{3}x+3x+3
Divide 9 by 3 to get 3.
y=\frac{8}{3}x+3
Combine -\frac{1}{3}x and 3x to get \frac{8}{3}x.
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Limits
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