Solve for y
y=\left(x-9\right)\left(x-7\right)^{2}+10
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y=\left(x^{2}-14x+49\right)\left(x-9\right)+10
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-7\right)^{2}.
y=x^{3}-23x^{2}+175x-441+10
Use the distributive property to multiply x^{2}-14x+49 by x-9 and combine like terms.
y=x^{3}-23x^{2}+175x-431
Add -441 and 10 to get -431.
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