Solve for y
y=\left(x-6\right)\left(\left(x-5\right)^{2}+x-4\right)
Solve for x
x=\sqrt[3]{y+1}+5
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y=x^{3}-15x^{2}+75x-125-1
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-5\right)^{3}.
y=x^{3}-15x^{2}+75x-126
Subtract 1 from -125 to get -126.
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