Solve for y
y=\left(x-4\right)^{3}
Solve for x
x=\sqrt[3]{y}+4
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y=x^{3}-12x^{2}+48x-64
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-4\right)^{3}.
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