Solve for y
y=-\left(-\left(x+3\right)\left(x-3\right)^{2}+4\right)
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y=\left(x^{2}-6x+9\right)\left(x+3\right)-4
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
y=x^{3}-3x^{2}-9x+27-4
Use the distributive property to multiply x^{2}-6x+9 by x+3 and combine like terms.
y=x^{3}-3x^{2}-9x+23
Subtract 4 from 27 to get 23.
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