y = ( x - 2,5 ) ^ { 2 } - 1
Solve for y
y=\left(x-3,5\right)\left(x-1,5\right)
Solve for x
x=-\sqrt{y+1}+2,5
x=\sqrt{y+1}+2,5\text{, }y\geq -1
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y=x^{2}-5x+6,25-1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2,5\right)^{2}.
y=x^{2}-5x+5,25
Subtract 1 from 6,25 to get 5,25.
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