Solve for y
y=\left(x-2\right)^{2}+10
Solve for x (complex solution)
x=-\sqrt{y-10}+2
x=\sqrt{y-10}+2
Solve for x
x=-\sqrt{y-10}+2
x=\sqrt{y-10}+2\text{, }y\geq 10
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y=x^{2}-4x+4+10
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
y=x^{2}-4x+14
Add 4 and 10 to get 14.
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