Solve for y
y=\left(x+3\right)\left(x+7\right)^{2}+35
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y=\left(x^{2}+14x+49\right)\left(x+3\right)+35
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+7\right)^{2}.
y=x^{3}+17x^{2}+91x+147+35
Use the distributive property to multiply x^{2}+14x+49 by x+3 and combine like terms.
y=x^{3}+17x^{2}+91x+182
Add 147 and 35 to get 182.
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