Solve for y
y=\left(x+3\right)^{2}+3
Solve for x (complex solution)
x=-\left(\sqrt{y-3}+3\right)
x=\sqrt{y-3}-3
Solve for x
x=-\left(\sqrt{y-3}+3\right)
x=\sqrt{y-3}-3\text{, }y\geq 3
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y=x^{2}+6x+9+3
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
y=x^{2}+6x+12
Add 9 and 3 to get 12.
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