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y=x^{2}-4-\left(x-1\right)^{2}
Consider \left(x+2\right)\left(x-2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 2.
y=x^{2}-4-\left(x^{2}-2x+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
y=x^{2}-4-x^{2}+2x-1
To find the opposite of x^{2}-2x+1, find the opposite of each term.
y=-4+2x-1
Combine x^{2} and -x^{2} to get 0.
y=-5+2x
Subtract 1 from -4 to get -5.
-5+2x=y
Swap sides so that all variable terms are on the left hand side.
2x=y+5
Add 5 to both sides.
\frac{2x}{2}=\frac{y+5}{2}
Divide both sides by 2.
x=\frac{y+5}{2}
Dividing by 2 undoes the multiplication by 2.
y=x^{2}-4-\left(x-1\right)^{2}
Consider \left(x+2\right)\left(x-2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 2.
y=x^{2}-4-\left(x^{2}-2x+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
y=x^{2}-4-x^{2}+2x-1
To find the opposite of x^{2}-2x+1, find the opposite of each term.
y=-4+2x-1
Combine x^{2} and -x^{2} to get 0.
y=-5+2x
Subtract 1 from -4 to get -5.