Solve for y
y=\left(x+2\right)^{3}-3
Solve for x
x=\sqrt[3]{y+3}-2
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y=x^{3}+6x^{2}+12x+8-3
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+2\right)^{3}.
y=x^{3}+6x^{2}+12x+5
Subtract 3 from 8 to get 5.
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