Solve y=(b_{0})+(b_{1})x

$$y = ( b _ { 0 } ) + ( b _ { 1 } ) x$$

Solve for b_1 (complex solution)

$$\left\{\begin{matrix}b_{1}=-\frac{b_{0}-y}{x}\text{, }&x\neq 0\\b_{1}\in \mathrm{C}\text{, }&y=b_{0}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$b_{0}+b_{1}x=y$$

Subtract b_{0} from both sides.

$$b_{1}x=y-b_{0}$$

The equation is in standard form.

$$xb_{1}=y-b_{0}$$

Divide both sides by x.

$$\frac{xb_{1}}{x}=\frac{y-b_{0}}{x}$$

Dividing by x undoes the multiplication by x.

$$b_{1}=\frac{y-b_{0}}{x}$$

Solve for b_0

$$b_{0}=y-b_{1}x$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$b_{0}+b_{1}x=y$$

Subtract b_{1}x from both sides.

$$b_{0}=y-b_{1}x$$

Solve for b_1

$$\left\{\begin{matrix}b_{1}=-\frac{b_{0}-y}{x}\text{, }&x\neq 0\\b_{1}\in \mathrm{R}\text{, }&y=b_{0}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$b_{0}+b_{1}x=y$$

Subtract b_{0} from both sides.

$$b_{1}x=y-b_{0}$$

The equation is in standard form.

$$xb_{1}=y-b_{0}$$

Divide both sides by x.

$$\frac{xb_{1}}{x}=\frac{y-b_{0}}{x}$$

Dividing by x undoes the multiplication by x.

$$b_{1}=\frac{y-b_{0}}{x}$$