Solve y=(8x^2-4x-2)(3x+6)text{at}x=2

$$y = ( 8 x ^ { 2 } - 4 x - 2 ) ( 3 x + 6 ) \text { at } x = 2$$

Solve for y, x

$$x=2$$

$$y=264$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=\left(8\times 2^{2}-4\times 2-2\right)\left(3\times 2+6\right)$$

Calculate 2 to the power of 2 and get 4.

$$y=\left(8\times 4-4\times 2-2\right)\left(3\times 2+6\right)$$

Multiply 8 and 4 to get 32.

$$y=\left(32-4\times 2-2\right)\left(3\times 2+6\right)$$

Multiply -4 and 2 to get -8.

$$y=\left(32-8-2\right)\left(3\times 2+6\right)$$

Subtract 8 from 32 to get 24.

$$y=\left(24-2\right)\left(3\times 2+6\right)$$

Subtract 2 from 24 to get 22.

$$y=22\left(3\times 2+6\right)$$

Multiply 3 and 2 to get 6.

$$y=22\left(6+6\right)$$

Add 6 and 6 to get 12.

$$y=22\times 12$$

Multiply 22 and 12 to get 264.

$$y=264$$

The system is now solved.

$$y=264 x=2$$