Solve y=(7x^4-x+3)(-x^5+3)

$$y = ( 7 x ^ { 4 } - x + 3 ) ( - x ^ { 5 } + 3 )$$

Solve for y

$$y=\left(7x^{4}-x+3\right)\left(3-x^{5}\right)$$

Solution Steps

Use the distributive property to multiply 7x^{4}-x+3 by -x^{5}+3.

$$y=7x^{4}\left(-x^{5}\right)+21x^{4}-x\left(-x^{5}\right)-3x+3\left(-x^{5}\right)+9$$

Multiply -1 and -1 to get 1.

$$y=7x^{4}\left(-x^{5}\right)+21x^{4}+xx^{5}-3x+3\left(-x^{5}\right)+9$$

To multiply powers of the same base, add their exponents. Add 1 and 5 to get 6.

$$y=7x^{4}\left(-x^{5}\right)+21x^{4}+x^{6}-3x+3\left(-x^{5}\right)+9$$

To multiply powers of the same base, add their exponents. Add 4 and 5 to get 9.

$$y=7x^{9}\left(-1\right)+21x^{4}+x^{6}-3x+3\left(-1\right)x^{5}+9$$

Multiply 7 and -1 to get -7.

$$y=-7x^{9}+21x^{4}+x^{6}-3x+3\left(-1\right)x^{5}+9$$

Multiply 3 and -1 to get -3.

$$y=-7x^{9}+21x^{4}+x^{6}-3x-3x^{5}+9$$