Solve for y
y=\left(2-x\right)^{2}-2
Solve for x (complex solution)
x=\sqrt{y+2}+2
x=-\sqrt{y+2}+2
Solve for x
x=\sqrt{y+2}+2
x=-\sqrt{y+2}+2\text{, }y\geq -2
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y=4-4x+x^{2}-2
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2-x\right)^{2}.
y=2-4x+x^{2}
Subtract 2 from 4 to get 2.
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