Solve for y
y=\frac{\left(x-2\right)^{2}-10}{5}
Solve for x
x=-\sqrt{5\left(y+2\right)}+2
x=\sqrt{5\left(y+2\right)}+2\text{, }y\geq -2
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y=\frac{1}{5}\left(x^{2}-4x+4\right)-2
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
y=\frac{1}{5}x^{2}-\frac{4}{5}x+\frac{4}{5}-2
Use the distributive property to multiply \frac{1}{5} by x^{2}-4x+4.
y=\frac{1}{5}x^{2}-\frac{4}{5}x-\frac{6}{5}
Subtract 2 from \frac{4}{5} to get -\frac{6}{5}.
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