Solve for y
y=\frac{\left(x+24\right)^{3}}{64}
Solve for x
x=4\left(\sqrt[3]{y}-6\right)
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y=\frac{1}{64}x^{3}+\frac{9}{8}x^{2}+27x+216
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(\frac{1}{4}x+6\right)^{3}.
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