Solve for y
y=\frac{\left(1-3x\right)^{3}}{27}
Solve for x
x=-\sqrt[3]{y}+\frac{1}{3}
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y=\frac{1}{27}-\frac{1}{3}x+x^{2}-x^{3}
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(\frac{1}{3}-x\right)^{3}.
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