Solve y=(1/2)^2-2*1/2-3

$$y = ( \frac { 1 } { 2 } ) ^ { 2 } - 2 \times \frac { 1 } { 2 } - 3$$

Solve for y

$$y = -\frac{15}{4} = -3\frac{3}{4} = -3.75$$

Steps for Solving Linear Equation

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$y=\frac{1}{4}-2\times \frac{1}{2}-3$$

Cancel out 2 and 2.

$$y=\frac{1}{4}-1-3$$

Convert 1 to fraction \frac{4}{4}.

$$y=\frac{1}{4}-\frac{4}{4}-3$$

Since \frac{1}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$y=\frac{1-4}{4}-3$$

Subtract 4 from 1 to get -3.

$$y=-\frac{3}{4}-3$$

Convert 3 to fraction \frac{12}{4}.

$$y=-\frac{3}{4}-\frac{12}{4}$$

Since -\frac{3}{4} and \frac{12}{4} have the same denominator, subtract them by subtracting their numerators.

$$y=\frac{-3-12}{4}$$

Subtract 12 from -3 to get -15.

$$y=-\frac{15}{4}$$

Assign y

$$y≔-\frac{15}{4}$$