Solve for x
x=y^{2}+16
y\geq 0
Solve for x (complex solution)
x=y^{2}+16
arg(y)<\pi \text{ or }y=0
Solve for y
y=\sqrt{x-16}
x\geq 16
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\sqrt{x-16}=y
Swap sides so that all variable terms are on the left hand side.
x-16=y^{2}
Square both sides of the equation.
x-16-\left(-16\right)=y^{2}-\left(-16\right)
Add 16 to both sides of the equation.
x=y^{2}-\left(-16\right)
Subtracting -16 from itself leaves 0.
x=y^{2}+16
Subtract -16 from y^{2}.
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