Solve y=sqrt{9^2}+b_2^2

$$y = \sqrt { 9 ^ { 2 } } + b _ { 2 } ^ { 2 }$$

Solve for y

$$y=b_{2}^{2}+9$$

Solution Steps

Calculate 9 to the power of 2 and get 81.

$$y=\sqrt{81}+b_{2}^{2}$$

Calculate the square root of 81 and get 9.

$$y=9+b_{2}^{2}$$

Solve for b_2 (complex solution)

$$b_{2}=-\sqrt{y-9}$$

$$b_{2}=\sqrt{y-9}$$

Solve for b_2

$$b_{2}=\sqrt{y-9}$$

$$b_{2}=-\sqrt{y-9}\text{, }y\geq 9$$