y = \sqrt { 2 x - 1 } d x
Solve for d
\left\{\begin{matrix}d=\frac{y}{\sqrt{2x-1}x}\text{, }&x>\frac{1}{2}\\d\in \mathrm{R}\text{, }&x=\frac{1}{2}\text{ and }y=0\end{matrix}\right.
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\sqrt{2x-1}dx=y
Swap sides so that all variable terms are on the left hand side.
\sqrt{2x-1}xd=y
The equation is in standard form.
\frac{\sqrt{2x-1}xd}{\sqrt{2x-1}x}=\frac{y}{\sqrt{2x-1}x}
Divide both sides by \sqrt{2x-1}x.
d=\frac{y}{\sqrt{2x-1}x}
Dividing by \sqrt{2x-1}x undoes the multiplication by \sqrt{2x-1}x.
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