Solve y=sqrt{16-x}

$$y = \sqrt { 16 - x }$$

Solve for x

$$x=16-y^{2}$$

$$y\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{16-x}=y$$

Square both sides of the equation.

$$-x+16=y^{2}$$

Subtract 16 from both sides of the equation.

$$-x+16-16=y^{2}-16$$

Subtracting 16 from itself leaves 0.

$$-x=y^{2}-16$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{y^{2}-16}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{y^{2}-16}{-1}$$

Divide y^{2}-16 by -1.

$$x=16-y^{2}$$

Solve for x (complex solution)

$$x=16-y^{2}$$

$$arg(y)<\pi \text{ or }y=0$$

Solve for y

$$y=\sqrt{16-x}$$

$$x\leq 16$$