Solve y=sece^2x+e^2secx

$$y = \sec e ^ { 2 x } + e ^ { 2 \sec x }$$

Solve for y (complex solution)

$$y=\frac{e^{\frac{ie^{\left(2-i\right)x}+ie^{\left(2+i\right)x}+4}{2\cos(x)}}+e^{\frac{-ie^{\left(2-i\right)x}-ie^{\left(2+i\right)x}+4}{2\cos(x)}}+2}{2\cos(\left(e^{x}\right)^{2})}$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{2}\in \mathrm{Z}\text{ : }x=\frac{\ln(2\pi n_{1}+\frac{\pi }{2})}{2}+\pi n_{2}i\right)\text{ and }\nexists n_{3}\in \mathrm{Z}\text{ : }\left(\exists n_{4}\in \mathrm{Z}\text{ : }x=\frac{\ln(2\pi n_{3}+\frac{3\pi }{2})}{2}+\pi n_{4}i\right)\text{ and }\nexists n_{5}\in \mathrm{Z}\text{ : }x=\pi n_{5}+\frac{\pi }{2}$$

Solve for y

$$\left\{\begin{matrix}y=\frac{1}{\cos(e^{2x})}+e^{\frac{2}{\cos(x)}}\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }x=\frac{\ln(\pi n_{1}+\frac{\pi }{2})}{2}\text{ and }\nexists n_{2}\in \mathrm{Z}\text{ : }x=\pi n_{2}+\frac{\pi }{2}\\y\in \mathrm{R}\text{, }&-\cos(\left(e^{x}\right)^{2})\left(e^{\frac{1}{\cos(x)}}\right)^{2}-1=0\text{ and }\nexists n_{2}\in \mathrm{Z}\text{ : }x=\frac{\pi \left(2n_{2}+1\right)}{2}\text{ and }\exists n_{3}\in \mathrm{Z}\text{ : }x=\frac{\ln(2n_{3}+1)+\ln(\pi )-\ln(2)}{2}\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }x=\frac{\ln(\frac{\pi \left(2n_{1}+1\right)}{2})}{2}\end{matrix}\right.$$