Solve y=x-3/x+3

$$y = \frac { x - 3 } { x + 3 }$$

Solve for x

$$x=-\frac{3\left(y+1\right)}{y-1}$$

$$y\neq 1$$

Steps for Solving Linear Equation

Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by x+3.

$$y\left(x+3\right)=x-3$$

Use the distributive property to multiply y by x+3.

$$yx+3y=x-3$$

Subtract x from both sides.

$$yx+3y-x=-3$$

Subtract 3y from both sides.

$$yx-x=-3-3y$$

Combine all terms containing x.

$$\left(y-1\right)x=-3-3y$$

The equation is in standard form.

$$\left(y-1\right)x=-3y-3$$

Divide both sides by y-1.

$$\frac{\left(y-1\right)x}{y-1}=\frac{-3y-3}{y-1}$$

Dividing by y-1 undoes the multiplication by y-1.

$$x=\frac{-3y-3}{y-1}$$

Divide -3-3y by y-1.

$$x=-\frac{3\left(y+1\right)}{y-1}$$

Variable x cannot be equal to -3.

$$x=-\frac{3\left(y+1\right)}{y-1}\text{, }x\neq -3$$

Solve for y

$$y=-\frac{3-x}{x+3}$$

$$x\neq -3$$