Solve for x
x=-\frac{y+3}{y-1}
y\neq 1
Solve for y
y=-\frac{3-x}{x+1}
x\neq -1
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y\left(x+1\right)=x-3
Variable x cannot be equal to -1 since division by zero is not defined. Multiply both sides of the equation by x+1.
yx+y=x-3
Use the distributive property to multiply y by x+1.
yx+y-x=-3
Subtract x from both sides.
yx-x=-3-y
Subtract y from both sides.
\left(y-1\right)x=-3-y
Combine all terms containing x.
\left(y-1\right)x=-y-3
The equation is in standard form.
\frac{\left(y-1\right)x}{y-1}=\frac{-y-3}{y-1}
Divide both sides by y-1.
x=\frac{-y-3}{y-1}
Dividing by y-1 undoes the multiplication by y-1.
x=-\frac{y+3}{y-1}
Divide -3-y by y-1.
x=-\frac{y+3}{y-1}\text{, }x\neq -1
Variable x cannot be equal to -1.
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