Solve for x
x=\frac{7y}{y-1}
y\neq 1
Solve for y
y=\frac{x}{x-7}
x\neq 7
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y\left(x-7\right)=x
Variable x cannot be equal to 7 since division by zero is not defined. Multiply both sides of the equation by x-7.
yx-7y=x
Use the distributive property to multiply y by x-7.
yx-7y-x=0
Subtract x from both sides.
yx-x=7y
Add 7y to both sides. Anything plus zero gives itself.
\left(y-1\right)x=7y
Combine all terms containing x.
\frac{\left(y-1\right)x}{y-1}=\frac{7y}{y-1}
Divide both sides by y-1.
x=\frac{7y}{y-1}
Dividing by y-1 undoes the multiplication by y-1.
x=\frac{7y}{y-1}\text{, }x\neq 7
Variable x cannot be equal to 7.
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