Solve y=x/8+36/8=

$$y = \frac { x } { 8 } + \frac { 36 } { 8 } =$$

Solve for x

$$x=8y-36$$

Steps for Solving Linear Equation

Reduce the fraction \frac{36}{8} to lowest terms by extracting and canceling out 4.

$$y=\frac{x}{8}+\frac{9}{2}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 8 and 2 is 8. Multiply \frac{9}{2} times \frac{4}{4}.

$$y=\frac{x}{8}+\frac{9\times 4}{8}$$

Since \frac{x}{8} and \frac{9\times 4}{8} have the same denominator, add them by adding their numerators.

$$y=\frac{x+9\times 4}{8}$$

Do the multiplications in x+9\times 4.

$$y=\frac{x+36}{8}$$

Divide each term of x+36 by 8 to get \frac{1}{8}x+\frac{9}{2}.

$$y=\frac{1}{8}x+\frac{9}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{8}x+\frac{9}{2}=y$$

Subtract \frac{9}{2} from both sides.

$$\frac{1}{8}x=y-\frac{9}{2}$$

Multiply both sides by 8.

$$\frac{\frac{1}{8}x}{\frac{1}{8}}=\frac{y-\frac{9}{2}}{\frac{1}{8}}$$

Dividing by \frac{1}{8} undoes the multiplication by \frac{1}{8}.

$$x=\frac{y-\frac{9}{2}}{\frac{1}{8}}$$

Divide y-\frac{9}{2} by \frac{1}{8} by multiplying y-\frac{9}{2} by the reciprocal of \frac{1}{8}.

$$x=8y-36$$

Solve for y

$$y=\frac{x+36}{8}$$

Short Solution Steps

Reduce the fraction \frac{36}{8} to lowest terms by extracting and canceling out 4.

$$y=\frac{x}{8}+\frac{9}{2}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 8 and 2 is 8. Multiply \frac{9}{2} times \frac{4}{4}.

$$y=\frac{x}{8}+\frac{9\times 4}{8}$$

Since \frac{x}{8} and \frac{9\times 4}{8} have the same denominator, add them by adding their numerators.

$$y=\frac{x+9\times 4}{8}$$

Do the multiplications in x+9\times 4.

$$y=\frac{x+36}{8}$$

Divide each term of x+36 by 8 to get \frac{1}{8}x+\frac{9}{2}.

$$y=\frac{1}{8}x+\frac{9}{2}$$