Solve y=x/3+61/3

$$y = \frac { x } { 3 } + 6 \frac { 1 } { 3 }$$

Solve for x

$$x=3y-19$$

Steps for Solving Linear Equation

Multiply 6 and 3 to get 18.

$$y=\frac{x}{3}+\frac{18+1}{3}$$

Add 18 and 1 to get 19.

$$y=\frac{x}{3}+\frac{19}{3}$$

Since \frac{x}{3} and \frac{19}{3} have the same denominator, add them by adding their numerators.

$$y=\frac{x+19}{3}$$

Divide each term of x+19 by 3 to get \frac{1}{3}x+\frac{19}{3}.

$$y=\frac{1}{3}x+\frac{19}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x+\frac{19}{3}=y$$

Subtract \frac{19}{3} from both sides.

$$\frac{1}{3}x=y-\frac{19}{3}$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y-\frac{19}{3}}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{y-\frac{19}{3}}{\frac{1}{3}}$$

Divide y-\frac{19}{3} by \frac{1}{3} by multiplying y-\frac{19}{3} by the reciprocal of \frac{1}{3}.

$$x=3y-19$$

Solve for y

$$y=\frac{x+19}{3}$$

Solution Steps

Multiply 6 and 3 to get 18.

$$y=\frac{x}{3}+\frac{18+1}{3}$$

Add 18 and 1 to get 19.

$$y=\frac{x}{3}+\frac{19}{3}$$

Since \frac{x}{3} and \frac{19}{3} have the same denominator, add them by adding their numerators.

$$y=\frac{x+19}{3}$$

Divide each term of x+19 by 3 to get \frac{1}{3}x+\frac{19}{3}.

$$y=\frac{1}{3}x+\frac{19}{3}$$