Solve y=8x-5/3-2x

$$y = \frac { 8 x - 5 } { 3 - 2 x }$$

Solve for x

$$x=\frac{3y+5}{2\left(y+4\right)}$$

$$y\neq -4$$

Steps for Solving Linear Equation

Variable x cannot be equal to \frac{3}{2} since division by zero is not defined. Multiply both sides of the equation by -2x+3.

$$y\left(-2x+3\right)=8x-5$$

Use the distributive property to multiply y by -2x+3.

$$-2yx+3y=8x-5$$

Subtract 8x from both sides.

$$-2yx+3y-8x=-5$$

Subtract 3y from both sides.

$$-2yx-8x=-5-3y$$

Combine all terms containing x.

$$\left(-2y-8\right)x=-5-3y$$

The equation is in standard form.

$$\left(-2y-8\right)x=-3y-5$$

Divide both sides by -2y-8.

$$\frac{\left(-2y-8\right)x}{-2y-8}=\frac{-3y-5}{-2y-8}$$

Dividing by -2y-8 undoes the multiplication by -2y-8.

$$x=\frac{-3y-5}{-2y-8}$$

Divide -5-3y by -2y-8.

$$x=\frac{3y+5}{2\left(y+4\right)}$$

Variable x cannot be equal to \frac{3}{2}.

$$x=\frac{3y+5}{2\left(y+4\right)}\text{, }x\neq \frac{3}{2}$$

Solve for y

$$y=-\frac{5-8x}{3-2x}$$

$$x\neq \frac{3}{2}$$