Solve for x
x=-\frac{2y}{8-y}
y\neq 8
Solve for y
y=\frac{8x}{x-2}
x\neq 2
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y\left(x-2\right)=8x
Variable x cannot be equal to 2 since division by zero is not defined. Multiply both sides of the equation by x-2.
yx-2y=8x
Use the distributive property to multiply y by x-2.
yx-2y-8x=0
Subtract 8x from both sides.
yx-8x=2y
Add 2y to both sides. Anything plus zero gives itself.
\left(y-8\right)x=2y
Combine all terms containing x.
\frac{\left(y-8\right)x}{y-8}=\frac{2y}{y-8}
Divide both sides by y-8.
x=\frac{2y}{y-8}
Dividing by y-8 undoes the multiplication by y-8.
x=\frac{2y}{y-8}\text{, }x\neq 2
Variable x cannot be equal to 2.
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