Solve for x
x=-\frac{9-7y}{3y-7}
y\neq \frac{7}{3}
Solve for y
y=-\frac{9-7x}{3x-7}
x\neq \frac{7}{3}
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y\left(3x-7\right)=7x-9
Variable x cannot be equal to \frac{7}{3} since division by zero is not defined. Multiply both sides of the equation by 3x-7.
3yx-7y=7x-9
Use the distributive property to multiply y by 3x-7.
3yx-7y-7x=-9
Subtract 7x from both sides.
3yx-7x=-9+7y
Add 7y to both sides.
\left(3y-7\right)x=-9+7y
Combine all terms containing x.
\left(3y-7\right)x=7y-9
The equation is in standard form.
\frac{\left(3y-7\right)x}{3y-7}=\frac{7y-9}{3y-7}
Divide both sides by 3y-7.
x=\frac{7y-9}{3y-7}
Dividing by 3y-7 undoes the multiplication by 3y-7.
x=\frac{7y-9}{3y-7}\text{, }x\neq \frac{7}{3}
Variable x cannot be equal to \frac{7}{3}.
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