Solve y=7x-8/3-3

$$y = \frac { 7 x - 8 } { 3 } - 3$$

Solve for x

$$x=\frac{3y+17}{7}$$

Steps for Solving Linear Equation

Divide each term of 7x-8 by 3 to get \frac{7}{3}x-\frac{8}{3}.

$$y=\frac{7}{3}x-\frac{8}{3}-3$$

Subtract 3 from -\frac{8}{3} to get -\frac{17}{3}.

$$y=\frac{7}{3}x-\frac{17}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{7}{3}x-\frac{17}{3}=y$$

Add \frac{17}{3} to both sides.

$$\frac{7}{3}x=y+\frac{17}{3}$$

Divide both sides of the equation by \frac{7}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{7}{3}x}{\frac{7}{3}}=\frac{y+\frac{17}{3}}{\frac{7}{3}}$$

Dividing by \frac{7}{3} undoes the multiplication by \frac{7}{3}.

$$x=\frac{y+\frac{17}{3}}{\frac{7}{3}}$$

Divide y+\frac{17}{3} by \frac{7}{3} by multiplying y+\frac{17}{3} by the reciprocal of \frac{7}{3}.

$$x=\frac{3y+17}{7}$$

Solve for y

$$y=\frac{7x-17}{3}$$

Solution Steps

Divide each term of 7x-8 by 3 to get \frac{7}{3}x-\frac{8}{3}.

$$y=\frac{7}{3}x-\frac{8}{3}-3$$

Subtract 3 from -\frac{8}{3} to get -\frac{17}{3}.

$$y=\frac{7}{3}x-\frac{17}{3}$$