Solve for x
x=\frac{4\left(y+1\right)}{7}
Solve for y
y=\frac{7x}{4}-1
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\frac{7}{4}x-1=y
Swap sides so that all variable terms are on the left hand side.
\frac{7}{4}x=y+1
Add 1 to both sides.
\frac{\frac{7}{4}x}{\frac{7}{4}}=\frac{y+1}{\frac{7}{4}}
Divide both sides of the equation by \frac{7}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y+1}{\frac{7}{4}}
Dividing by \frac{7}{4} undoes the multiplication by \frac{7}{4}.
x=\frac{4y+4}{7}
Divide y+1 by \frac{7}{4} by multiplying y+1 by the reciprocal of \frac{7}{4}.
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