Solve for x
x=-\frac{5y+3}{2\left(y-2\right)}
y\neq 2
Solve for y
y=-\frac{3-4x}{2x+5}
x\neq -\frac{5}{2}
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y\left(2x+5\right)=4x-3
Variable x cannot be equal to -\frac{5}{2} since division by zero is not defined. Multiply both sides of the equation by 2x+5.
2yx+5y=4x-3
Use the distributive property to multiply y by 2x+5.
2yx+5y-4x=-3
Subtract 4x from both sides.
2yx-4x=-3-5y
Subtract 5y from both sides.
\left(2y-4\right)x=-3-5y
Combine all terms containing x.
\left(2y-4\right)x=-5y-3
The equation is in standard form.
\frac{\left(2y-4\right)x}{2y-4}=\frac{-5y-3}{2y-4}
Divide both sides by 2y-4.
x=\frac{-5y-3}{2y-4}
Dividing by 2y-4 undoes the multiplication by 2y-4.
x=-\frac{5y+3}{2\left(y-2\right)}
Divide -3-5y by 2y-4.
x=-\frac{5y+3}{2\left(y-2\right)}\text{, }x\neq -\frac{5}{2}
Variable x cannot be equal to -\frac{5}{2}.
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