Solve y=4x+2/3x

$$y = \frac { 4 x + 2 } { 3 x }$$

Solve for x

$$x=\frac{2}{3y-4}$$

$$y\neq \frac{4}{3}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 3x.

$$y\times 3x=4x+2$$

Subtract 4x from both sides.

$$y\times 3x-4x=2$$

Combine all terms containing x.

$$\left(y\times 3-4\right)x=2$$

The equation is in standard form.

$$\left(3y-4\right)x=2$$

Divide both sides by 3y-4.

$$\frac{\left(3y-4\right)x}{3y-4}=\frac{2}{3y-4}$$

Dividing by 3y-4 undoes the multiplication by 3y-4.

$$x=\frac{2}{3y-4}$$

Variable x cannot be equal to 0.

$$x=\frac{2}{3y-4}\text{, }x\neq 0$$

Solve for y

$$y=\frac{4}{3}+\frac{2}{3x}$$

$$x\neq 0$$