Solve y=4/7sqrt{18-x}

$$y = \frac { 4 } { 7 } \sqrt { 18 - x }$$

Solve for x

$$x=-\frac{49y^{2}}{16}+18$$

$$y\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\frac{4}{7}\sqrt{18-x}=y$$

Divide both sides of the equation by \frac{4}{7}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{4}{7}\sqrt{-x+18}}{\frac{4}{7}}=\frac{y}{\frac{4}{7}}$$

Dividing by \frac{4}{7} undoes the multiplication by \frac{4}{7}.

$$\sqrt{-x+18}=\frac{y}{\frac{4}{7}}$$

Divide y by \frac{4}{7} by multiplying y by the reciprocal of \frac{4}{7}.

$$\sqrt{-x+18}=\frac{7y}{4}$$

Square both sides of the equation.

$$-x+18=\frac{49y^{2}}{16}$$

Subtract 18 from both sides of the equation.

$$-x+18-18=\frac{49y^{2}}{16}-18$$

Subtracting 18 from itself leaves 0.

$$-x=\frac{49y^{2}}{16}-18$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{\frac{49y^{2}}{16}-18}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{\frac{49y^{2}}{16}-18}{-1}$$

Divide \frac{49y^{2}}{16}-18 by -1.

$$x=-\frac{49y^{2}}{16}+18$$

Solve for x (complex solution)

$$x=-\frac{49y^{2}}{16}+18$$

$$arg(y)<\pi \text{ or }y=0$$

Solve for y (complex solution)

$$y=\frac{4\sqrt{18-x}}{7}$$

Solve for y

$$y=\frac{4\sqrt{18-x}}{7}$$

$$x\leq 18$$