Solve for x
x=\frac{3\left(y+4\right)}{4}
Solve for y
y=\frac{4\left(x-3\right)}{3}
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\frac{4}{3}x-4=y
Swap sides so that all variable terms are on the left hand side.
\frac{4}{3}x=y+4
Add 4 to both sides.
\frac{\frac{4}{3}x}{\frac{4}{3}}=\frac{y+4}{\frac{4}{3}}
Divide both sides of the equation by \frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y+4}{\frac{4}{3}}
Dividing by \frac{4}{3} undoes the multiplication by \frac{4}{3}.
x=\frac{3y}{4}+3
Divide y+4 by \frac{4}{3} by multiplying y+4 by the reciprocal of \frac{4}{3}.
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