Solve for x
x=-\frac{2-5y}{2y-3}
y\neq \frac{3}{2}
Solve for y
y=-\frac{2-3x}{2x-5}
x\neq \frac{5}{2}
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y\left(2x-5\right)=3x-2
Variable x cannot be equal to \frac{5}{2} since division by zero is not defined. Multiply both sides of the equation by 2x-5.
2yx-5y=3x-2
Use the distributive property to multiply y by 2x-5.
2yx-5y-3x=-2
Subtract 3x from both sides.
2yx-3x=-2+5y
Add 5y to both sides.
\left(2y-3\right)x=-2+5y
Combine all terms containing x.
\left(2y-3\right)x=5y-2
The equation is in standard form.
\frac{\left(2y-3\right)x}{2y-3}=\frac{5y-2}{2y-3}
Divide both sides by 2y-3.
x=\frac{5y-2}{2y-3}
Dividing by 2y-3 undoes the multiplication by 2y-3.
x=\frac{5y-2}{2y-3}\text{, }x\neq \frac{5}{2}
Variable x cannot be equal to \frac{5}{2}.
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