Solve y=3x+2/1-x

$$y = \frac { 3 x + 2 } { 1 - x }$$

Solve for x

$$x=\frac{y-2}{y+3}$$

$$y\neq -3$$

Steps for Solving Linear Equation

Variable x cannot be equal to 1 since division by zero is not defined. Multiply both sides of the equation by -x+1.

$$y\left(-x+1\right)=3x+2$$

Use the distributive property to multiply y by -x+1.

$$-yx+y=3x+2$$

Subtract 3x from both sides.

$$-yx+y-3x=2$$

Subtract y from both sides.

$$-yx-3x=2-y$$

Combine all terms containing x.

$$\left(-y-3\right)x=2-y$$

Divide both sides by -y-3.

$$\frac{\left(-y-3\right)x}{-y-3}=\frac{2-y}{-y-3}$$

Dividing by -y-3 undoes the multiplication by -y-3.

$$x=\frac{2-y}{-y-3}$$

Divide 2-y by -y-3.

$$x=-\frac{2-y}{y+3}$$

Variable x cannot be equal to 1.

$$x=-\frac{2-y}{y+3}\text{, }x\neq 1$$

Solve for y

$$y=\frac{3x+2}{1-x}$$

$$x\neq 1$$