Solve y=3-4x/6

$$y = \frac { 3 - 4 x } { 6 }$$

Solve for x

$$x=-\frac{3y}{2}+\frac{3}{4}$$

Steps for Solving Linear Equation

Divide each term of 3-4x by 6 to get \frac{1}{2}-\frac{2}{3}x.

$$y=\frac{1}{2}-\frac{2}{3}x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}-\frac{2}{3}x=y$$

Subtract \frac{1}{2} from both sides.

$$-\frac{2}{3}x=y-\frac{1}{2}$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y-\frac{1}{2}}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$x=\frac{y-\frac{1}{2}}{-\frac{2}{3}}$$

Divide y-\frac{1}{2} by -\frac{2}{3} by multiplying y-\frac{1}{2} by the reciprocal of -\frac{2}{3}.

$$x=-\frac{3y}{2}+\frac{3}{4}$$

Solve for y

$$y=-\frac{2x}{3}+\frac{1}{2}$$

Solution Steps

Divide each term of 3-4x by 6 to get \frac{1}{2}-\frac{2}{3}x.

$$y=\frac{1}{2}-\frac{2}{3}x$$